datele problemei sunt:
i.p.
{a,b,c}--------->{3,2,6}
c=a *b
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rezolvare:
invers proportional inseamna egalitate de produse
3a=2b=6c=k (k=coeficient de proportionalitate)
egalam fiecare termen cu k
3a=k-> a= [tex] \frac{k}{3} [/tex]
2b=k-> b=[tex] \frac{k}{2} [/tex]
6c=k->c=[tex] \frac{k}{6} [/tex]
Inlocuim in c=a *b
[tex] \frac{6k}{6} = \frac{k}{3} * \frac{k}{2}
[/tex] (amplificam si scapam de numitor)
6k=2k*3k
6k=6k
k=1
a=1/3
b=1/2
c=1/6
