ecuatia x²-4x+3=0 are solutiile x1=1 x2=3=>
x²-4x+3=(x-1)(x-3)
1/(x-1)(x-3)=A/(x-1)+B/(x-3)=...=[(A+B)-(3a+B)]/(x-1)(x-3)
Determini pe A si B prin identificare
Siste,
{A+B=0
{3A+B=1
A=1/2 B=-1/2
Integrala devine
F(x)=∫dx/2(x-1)-∫dx/2(x-3)=1/2ln(x-1)-1/2ln(x-3)+C=1/2ln(x-1)/(x-3)+c
