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Aratati ca 4a^2+26b^2-10ab+6b+10>0

Răspuns :

4a^2+26b^2-10ab+6b+10>0

4a^2+26b^2-10ab+6b+10=a^2-10ab+25b^2+b^2+6b+9+3a^2+1=
=(a-+5b)^2+(b+3)^2+3a^2+1>0
ptr ca  (a-+5b)^2>0  (b+3)^2>0  3a^2+1>0