Conform enuntului , avem:
a+b+c = 200 stiim ca c=b+20
a=2(b+c) => a=2b+2(b+20)=4b+40
inlocuim in prima relatie ...
4b+40 + b + b+20 = 200
6b = 140
[tex]b=23\frac{1}{3}[/tex]
[tex]c=23\frac{1}{3}+20=43\frac{1}{3}[/tex]
[tex]a=4\cdot23\frac{1}{3}+40=4\cdot\frac{70}{3}+40=133\frac{1}{3}[/tex]
