4. 2KClO3 => 2KCl + 3O2
2*122,5g KClO3...........3*22,4 L O2
x g KClO3....................12 L O2
x=245*12/67,2 = 43,75 g KClO3
n(eta) = mp/mt*100 = 43,75/49*100=89,3 ℅
5. 4Al + 3O2 => 2Al2O3
4*27g Al.........2*102g Al2O3
xg Al.................24 g Al2O3
x=12,7g Al (mp)
p=mp/mimp*100=>mimp=mp*100/p = 12,7*100/90= 14,11g Al tehnic
n=V/Vm=6,72/22,4 = 0,3 moli O2 consumați