pe 1,5 il voi scrie ca [tex] \frac{15}{10} = \frac{3}{2} [/tex] (fiindca am simplificat) si obtin:
[tex]( \frac{19}{3} - \frac{3}{2}) : \frac{4}{3} = [/tex]
Aduc la acelasi numitor in paranteza si am:
[tex]( \frac{38}{6} - \frac{9}{6}) * \frac{3}{4} =
\frac{29}{6} * \frac{3}{4} = \frac{87}{24} = \frac{29}{8} [/tex]
