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Apotema piramidei triunghiulare regulate VABC,cu inaltimea VO= \sqrt{13} si latura bazei AB=18 cm,este de ......cm

Răspuns :

apoteam piramidei (teo pitagora) = √(VO²+apotema bazei²)
apotema bazei = (1/3) AB√3/2=(1/3 )* 18√3/2=3√3

Apotema piramidei =√((√13)²+(3√3)²)= √(13+27)=√40=2√10 cm