👤

F:D-R f(x)=xla2-3x-4 rexolvarea VA rog

Răspuns :

x^2-3x-4=0
Δ=b²-4ac=(-3)²-4*1*(-4)=9+16=25
x1,2=(-b+-√Δ)/2a=(-(-3)+-√25)/2*1=(3+-5)/2
x1=(3+5)/2=8/2=4
x2=(3-5)/2=-2/2=-1