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2×3^2-3^2+3×(3+3×(3^1-3^4÷3^3)÷2017^0+0^2017+2^1

Răspuns :

2×9-9+[3+3×(3-81÷27)]÷1+0+17+2=18-9+(3+3×(3-3)÷1+19=9+(3+3×0)÷1+19=9+(3+0)÷1+19=9+3÷1+19=9+3+19=12+19=31