1.1sirul se mai scrie
(3^n+4^n)/(3*3^n+4*4^n).IL DAI PE 4^n factor comun fortat la numarator si numitor
4^n*[(3/4)^n+1]/4^n[3*(3/4)^n+4]=[(3/4)^n+1]/[(3*(3/4)^n+4]→1/4 pt ca (3/4)^n→0
lll. Adui sci scazi 1
lim[1-2x/(3-2x)]^(x²+1)/(x-1)
Ridici concomitent la puterea 2x/(3-2x) si tot odata la (3-2x)/2x obtii
e^lim(3-2x)/2x*(x²+1)/(x-1)=e^(-∞)=0
