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calculati : (3^3-3^2)÷3 = .......b) (7^2-2^3×3)^2-24= ........c) [2^2-(5^2-2^3×3)^47]^4÷27=

Răspuns :

(3^3-3^2)÷3 =3^2-3=9-3=6

b) (7^2-2^3×3)^2-24=(49-24)^2-24=25^2-24=625-24=601

c) [2^2-(5^2-2^3×3)^47]^4÷27=
=
[2^2-(25-24)^47]^4÷3^3=
=(4-1^47)^4÷3^3=
=(4-1)^4÷3^3=
=3^4
÷3^3= 3