ro=ms/Vs=>ms=ro*Vs=1,082*776,34=840g sol KOH
C=md/ms*100=>md=C*ms/100=10*840/100=84g KOH
n=m/M=84/56=1,5 moli KOH
ms=md+mH2O=>mH2O=ms-md=840-84=756g
2 moli......98g..............................2*18g
2KOH + H2SO4 => K2SO4 + 2H2O
1,5 moli....x=73,5g......................y=27g
C=md/ms*100=>ms=md*100/C=73,5*100/20=367,5g sol H2SO4
ms=md+mH2O=>mH2O=ms-md=367,5-73,5=294g
ro=ms/Vs=>Vs=ms/ro=367,5/1,143=321,522 mL sol H2SO4
mH2O final = 756+294+27=1077g