a×b=27216 si (a,b)=36
(a,b)×[a,b]=a×b
[a,b]=27216:36=756
[a,b]=756 si (a;b)=36
Daca
(a;b)=36⇒ a=36k, b=36p, k si p sunt nr. nat. nenule
⇒27216 = 36k × 36p=
27216= 1296 (k × p)⇒(k × p)=27216:1296=21
k×p=21
⇒ k si p sunt
divizori ai lui 21 adica D₂₁={1,3,7,21}
(1,21), (3,7)
a=36k, b=36p, a=36×1=36 si b=36×21=756
a=36×3=108.........b=36×7=252
deci perechile de numere pot fi (36, 756) (108, 252)
(756, 36) (252, 108)
