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rezolvati ecuatia 139+3x-[(2^2)^3]^5:(2^7)^4=198

Răspuns :

139+3x-[(2^2)^3]^5:(2^7)^4=198
139+3x-(2^6)^5:2^28=198
139+3x-2^30:2^28=198
139+3x-2^2=198
3x-4=59
3x=63
x=21.

Sper ca te-am ajutat :)