Este gresit textul_
izooctanul are 8 at.C si se numeste 2,2,4- trimetil pentan
CH3-C(CH3)2-CH2-CH(CH3)-CH3
C,.O, mica ,zero, o are n.heptanul
v=2l m=rox v---> m= 0,9g/mlx2000ml=1800g izooctan C8H18
M(miu)= (8x12gC+18gH)/mol=114g/mol
n(niu) =1800/114mol C8H18=15,79 mol
1mol C8H18.......8molC
15,79mol.........n=126,3 molC----> 126,3mol CO2
V= n x Vm; V,CO2= 126,3molx22,4l/mol=..................calculeaza !!!!