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Calculati media geometrica a numerelor :

a= ( √2 +1 ) (√3-√2)

b= (√2-1 ) (√3+√2)


Răspuns :

mg=√axb

axb=(√2+1)(√3-√2)(√2-1)(√3+√2)=(2-1)(3-2)=1
√axb=√1=1
mg=√a·b
mg=√(√2+1)(√2-1)(√3-√2)(√3+√2)
mg=√(2-1)(3-2)
mg=√1·1
mg=1⇒media geometrica a numerelor a si b;