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Determinati (S1 ; S2) in urmatoarele cazuri:-S1=1+2+3+...+32 si S2=1+2+3+...+39

Răspuns :

S1=1+2+3+...+32
S=[n×(n+1)]:2
S1=(32×33):2=
S1=528

S2=1+2+3+...+39
S2=(39×40):2=780

32×(32+1):2=33×16=528.....39×(39+1):2=39×20=780 gauss