150 cm³=150 ml
[tex]c= \frac{md}{ms} *100[/tex]
c=14,5%
md=cantitatea de zahar care trebuie adaugata
ms=m apa+md
[tex]c= \frac{md}{mapa+md} *100 [/tex]⇒[tex] 14,5=\frac{md}{md+150} *100[/tex]⇒100md=14,5(md+150)⇒100md-14,5md=2175⇒85,5md=2175⇒ md=[tex] \frac{2175}{85,5} [/tex] = 25,43 g zahar
R: cantitatea de zahar care trebuie dizolvata este de 25,43 g
