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a•a la a doua•a la a doua•.......•a la a zecea
Ma ajutati?


Răspuns :

[tex] a*a^2*a^3*...*a^{10}=a^{1+2+3+...+10}=a^{\frac{10*11}{2}}=a^{\frac{110}{2}}=a^{55} [/tex]
A).     ... = a¹⁺²⁺³⁺⁴⁺⁵⁺⁶⁺⁷⁺⁸⁺⁹⁺¹⁰ =a⁽¹⁰*¹¹⁾/² = a ⁵*¹¹ = a⁵⁵ .