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x+4y+2z=13 si 3x+2z=11 aflati x+y+z

Răspuns :


x+4y+2z=13
3x+2z=11  adunam cele doua relatii si rezulta 

(x+3x)+4y+(2z+2z)=13+11
4x+4y+4z=24
4(x+y+z)=6×4

x+y+z=6