Zn + 2HCl = Zn Cl2 + H2
dintr-un kmol zinc rezultă 1 kmol H2, adică
1kmol Zn................1 kmol H2
10kmoli Zn............x
x =10 kmoli H2
VH2= 10000 molix 22,4 l/mol= 224000L=224 m3
1kmol Zn-------2 kmoli HCl
10 Kmoli...........x
x = 20 kmoli HCl
m HCl= nxM= 20 kmoli x 36,5Kg/Kmol= 730 kg HCl pur(md)
c = md x 100/ms, ms = mdx100/c = 730x100/ 20=36500kg