pV=nRT=>n=pV/RT=5*0,492/0,082*300=0,1 moli H2 => are 1 leg. dubla
C=md/ms*100=>md=C*ms/100=2*400/100=8g Br2 => n=8/160=0,05 moli Br2
n=m/M=1,4/28=0,05 moli CxHy
0,05 moli CxHy.........................0,05 moli Br2
1 mol CxHy...............................x=1 mol Br2 => Hidrocarbura are 1 leg. dubla