a=echer b=compas c=raport . Aflam prin matrice daca ai trecut asta
( 4 7 6 ) (65)
A=( 7 4 5 ) B= (67) Aflam determinantele 4 (prin diagonale)
( 1 1 15 ) (68)
Δ=(4·4·15 +7·1·6+1·7·5)-(6·4·1+5·1·4+15·7·7)=
=(240+42+35)-(24+20+735)=317-779=(-462)
determinante
Fiecare coloana schimbam pe rind cu coloana din B , pentru celelalte
Δ1=(65·4·15+67·1·6+68·7·5)-(6·4·68+5·1·65+15·7·67)=
=(3900+402+2380)-(1632+325+7035)=6682-8992=(-2310)
Δ2=(4·67·15+7·68·6+1·65·5)-(6·67·1+5·68·4+15·65·7)=
=(4020+2856+325)-(402+1360+6825)=7201-8587=(-1386)
Δ3=(4·4·68+7·1·65+1·7·67)-(65·4·1+67·1·4+68·7·7)=
=(1088+455+469)-(260+268+3332)=2012-3860=(-1848)
Acuma:
a=Δ1 / Δ =(-2310)/(-462)=5 lei (echer)
b=Δ2 / Δ =(-1386)/(-462)=3 lei (compas)
c=Δ3 / Δ =(-1848)/(-462)=4 lei (raport)
AM aflat toooot!!!!!!!!!!! "_"
