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12 mai mic sau egal x-3 mai mic sau egal 27

Răspuns :

12≤x-3≤27/(+3)⇒15≤x≤30⇒x∈[15,30]
12 ≤ x-3 ≤ 27  | +3
15 ≤ x ≤ 30

Așadar,
x ∈ {15, 16, 17, ..., 30}
x ∈ [15; 30]