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(n+3) divide (n la puterea a doua + 6n+17) Aftai n !!!

Răspuns :

n^2+6n+17=(n+3)^2+8

(n+3) | (n+3)^2+8 <=>
n+3 | 8
n+3=4 => n=1
n+3=8 => n=5