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Ajutor!!!Se da:
m(Al)-5,4g
Aflati:
Niu(AlCl3)-?
m(Cl)-?


Răspuns :

2Al + 3Cl2 ==> 2AlCl3

2*27g Al....................2 moli AlCl3
5,4g Al.......................x moli AlCl3

x=2*5,4/54=0,2 moli AlCl3

2*27g Al.................3*71g Cl2
5,4g Al.....................xg Cl2

x=3*71*5,4/54 = Calculeaza !!