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aflati trei numere naturale abc care verifica simultan egalitatile


a+b=28 b+c=46 c+a=28


Răspuns :

a+b     = 28
    b+c = 46
a+    c = 28
__________________
2a+2b+2c = 28+46+28
2(a+b+c)= 102
a+b+c = 102:2
a+b+c = 51
28+c = 51
c = 51-28
c = 23
a+46 = 51
a = 51-46
a = 5
28+b = 51
b = 51-28
b = 23
Proba
5+23+23 = 28+23 = 51