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[tex] \sqrt{7+ 4\sqrt{3}} - \sqrt{7-4 \sqrt{3} } [/tex] urgent

Răspuns :

[tex] \sqrt{4+4 \sqrt{3}+3 } - \sqrt{4-4 \sqrt{3}+3 } = \sqrt{(2+ \sqrt{3}) ^{2} } - \sqrt{ (2- \sqrt{3} )^{2} } = 2+ \sqrt{3} -2+ \sqrt{3} =2 \sqrt{3} [/tex]