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[tex]( x^{2} + x)^{2} -3( x^{2} +x)+2=0[/tex]

Răspuns :

x⁴+2x³+x²-3x⁴-6x³-3x²=0
-2x⁴-4x³-2x²=0
-2x²(x²+2x+1)=0
sistem :
1) -2x²=0 ⇔ x²=0 ⇔ x=0
2) x²+2x+1=0
Delta= 4-4=0
x=-2/2=-1
inlocuim 0 apoi -1 in ecuatie ⇒ numai -1 poate fi solutia ecuatiei.
S={ -1 }