fie a b c d masurile unghiurilor patrulaterului conex
a+b+c+d=360
(a,b,c,d) d.p.(1,2,2,3)
[tex] \frac{a}{1}= \frac{b}{2}= \frac{c}{2}= \frac{d}{3} [/tex]
[tex] \frac{b}{2}=a [/tex] ⇒b=2a
[tex] \frac{c}{2}=a [/tex] ⇒c=2a
[tex] \frac{d}{3}=a [/tex] ⇒d=3a
a+2a+2a+3a=360
8a=360 ⇒a=45 ⇒b=2*45 c=2*45 d=3*45
b=90 c=90 d=135
masurile celor 4 unghiuri sunt : 45 , 90, 90, 135
