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√12-√6 supra √30-√15=?

Răspuns :

[tex] \frac{ \sqrt{12}- \sqrt{6} }{ \sqrt{30} - \sqrt{15} } = \frac{ \sqrt{6} ( \sqrt{2}-1 )}{ \sqrt{15}( \sqrt{2} -1) } = \frac{ \sqrt{6} }{ \sqrt{15} } = \sqrt{ \frac{6}{15} } = \sqrt{ \frac{2}{5} } [/tex]

(√12-√6)/(√30-√15) = √6(√2 - 1)/√15(√2 - 1) = √6/√15 =√(6/15) = 

= √(2/5) = √ 0,4 ≈ 0, 632