C/100= md/ms, unde ms= md+m,apa
-calculez masa de acid din solutie si masa de apa
36,5/100= md/300---> md= 109,5gHCl; m,apa= 300- 109,5=
-calculez masa de hidroxid din solutie si masa de apa
40/100= ,d/200---> md= 80gNaOH; m,apa= 200-80=
-ecuatia reactiei
1mol 1mol 1mol 1mol
HCl + NaOH ---> NaCl + H20
36,5g.....40g..........58,5g......18g
x.............80...............y...............z
x= 73g-->.acidul este in exces ; m,exces= 109,5-73 gHCl
y= 117gNaCl
z= 36g H2O
-SOLUTIA FINALA ESTE FORMATA DIN
md= m,excesHCl +mNaCl=(109,5-73)+117=.........
m,apa= m,reactie + m,sol acid+ m,sol baza
= 36+(300-109,5) +(200-80) =.........
ms= md+m,apa= ....... calculeaza !!
c/100=md/ms..............................calculeaza !!!!!
