a) Al + 3 HCl => AlCl3 + 3/2 H2
b) 3/2 moli H2........3*36.5 g HCl
0.2 moli H2..................x g HCl
x = 14.6 g HCl
c = md/ms*100 => ms = 14.6/16.5 * 100 = 884.84 g solutie HCl
c) 27 g Al............3/2 moli H2
x g Al...................0.2 moli
x = 3.6 g Al
m Cu = 18.2 - 3.6 = 14.6 g Cu
%Cu = 14.6/18.2 * 100 = 80.219%
%Al = 3.6/18.2 * 100 = 19,780%
d) n = nr molecule/nr lui Avogadro
nr molecule = 0,2 * 6.022 * 10^23 = 1,2044 * 10^23 molecule H2