ptr. x -2 ≥ 0 x ≥ 2 |x - 2| = x-2 |2x - 1| = 2x -1
(x - 2) (8-2x) > 0
a) x -2 > 0 x > 2 8-2x > 0 2x< 8 x < 4
x > 2 ∪ x < 4 ⇒ x = 3
b) 2x - 1 < 0 x < 1/2 |2x - 1| = 1-2x |x -2| = 2-x
(2-x)(6+2x) > 0
2-x > 0 x < 2 6 + 2x > 0 x > -3
x > -3 ∪ x <2 ⇒ x ∈ {-2,-1,0,1}
