f)
[tex]\it \dfrac{4n+11}{2n+3} = \dfrac{4n+6+5}{2n+3} = \dfrac{2(2n+3)+5}{2n+3} = \dfrac{2(2n+3)}{2n+3} +\dfrac{5}{2n+3} [/tex]
[tex]\it = 2 +\dfrac{5}{2n+3} \in {\mathbb{Z} \Rightarrow 2n+3|5 \Rightarrow 2n+3\in \{-5, -1, 1, 5\}|_{-3}\Rightarrow [/tex]
[tex]\it \Rightarrow 2n\in\{ -8, -4, -2, 2\}|_{:2} \Rightarrow x \in\{-4, \ -2,\ -1,\ 1\}[/tex]
