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Sa se determine formula moleculara a urmatorilor compusi halogenati
a) compusul monobromurat ceNE=0 ce contine 73,39%Br
b)compusul monoclorurat cu NE=1 cu masa molara egala cu 90,5 g/mol.


Răspuns :

CxHyBr
NE=0=>(2+2x-y-1)/2 = 0 => y = 2x+1
CxH2x+1Br
73,39 = 80/14x+81 * 100 => x = 2 => C2H5Br

CxHyCl
NE=1=>(2+2x-y-1)/2 = 1 => y = 2x-1
CxH2x-1Cl
14x-1+35.5 = 90.5 => x = 4 => C4H7Cl