a)mas A +masB=360°-113°=247°
mas A=2masB +10°
3mas B+10°=247°
3masB=237°
mas B=237°:3=79°
mas A=(2*79+10)°=168°
c) direct prop cu inversele
2;5;3;10/9=1,(1)
A/2=B/5=C/3=D/1, (1)= (A+B+C+D)/(2+3+5+1.(10))
proportii deriva,e
360/11.(1)=360/(100/9)=360*9/100=162/5=32,4
A=32,4*2=64,8°=64°48'
B=32,4*5=162°
C=32,4*3=97,2°=97°12'
D=32,4*10/9=36°