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Calculati 2+4+6...+88

Răspuns :

2+4+6...+88 =2(1+2+3+......+44)

(1+2+3+......+44) - suma Gauss , are formula de calcul [n(n+1)]:2


(1+2+3+......+44)=(44*45):2=990

deci suma initiala=2×990=1980

2+4+6...+88 =2(1+2+3+......+44)=2×990=1980