A(m, -1)∈Gf
f:R→R
[tex]f(x)= x^{2} -3x+1 [/tex]
Inlocuiesti x cu m si f(x) cu -1
[tex]-1= m^{2} -3m+1 \\ m^{2}-3m+1+1=0 \\m^{2}-3m+2=0 \\ d= (-3)^{2}-4*1*2 =9-8=1 \\ \\ m_{1} = \frac{3-1}{2}= \frac{2}{2}= 1 \\ \\ m_{2} \frac{3+1}{2}= \frac{4}{2}= 2 [/tex]
m∈{1, 2}
