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Daca a+b=4 si c=5 , calculati: (4a+c+4b)×[3c-(2a+2b)]
MULTUMESC ANTICIPAT


Răspuns :

4a+c+4b=4x4+5=21
3c-(2a+2b)=
3x5-4x2=
15-8=7
21x7=147
Daca a+b=4 si c=5 , calculati: (4a+c+4b)×[3c-(2a+2b)]
[4(a+b)+c]×[3c-2(a+b)]

(4×4+5)×(15-8)=
21×7=147

(4a+c+4b)×[3c-(2a+2b)] =147