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2.Reolva in doua moduri:
a) 7·(123 234 + 2372)=
b)21·47+1532·21-21·12=


Răspuns :

a) 1) 7*123234+7*2372=862638+16604=879242
    2) 7*(123234+2372)= 7*125606=879242

b) 1) 21(47+1532-12)=21*1567=32907
    2) 21*47+1532*21-21*12=987+32172-252=32907
a)Mod. 1
 7x(123234+2372)=7x125606=879242
Mod. 2
7x123234+7x2372=862638+16604=879242
b) Mod. 1
21x47+1532x21-21x12=987+32172-252=32907
 Mod. 2
21x(47+1532-12)=21x1567=32907