HOOC-CxHy-COOH + 2CH3-OH ⇒ H3C-OCO-CxHy-O-COCH3 + 2H2O
M acid = 90 + 12x +y
M ester = M acid - 34 + 62 = M + 28
M + 28 = 124,13/100 ·M 0, 2413M = 28 M = 116 M CxHy = 116-90 = 26
⇒⇒ x = 2 y = 2 acid : HOOC-CH=CH-COOH (X = ac. maleic; Y = ac. fumaric)
HOOC-CH=CH-COOH ⇒ C2H2(C2O3) + H2O
18g H2O = 1 mol ⇒⇒ n acid maleic = 1mol (m =116g) ⇒⇒
⇒⇒ m ac. fumaric = 116g ( n= 1 mol)
% ac. maleic = %ac. fumaric = 50%