CH3- CH2 - CH2-CH3 ⇄ CH3 - (CH3)CH - CH3
initial : 2moli (116g)
s-au izomerizat : x
final (2-x) x moli
1mol izobutan..........contin............12g C tertiar
x moli...............................................19,2g
x = 19,2/12 = 1,6 moli
K = [izobutan] /[butan] = (x/V) / (2-x)/V = 1,6/0,4 = 4