MSO4, unde M este metalul divalent
-c/100=md/ms--> 8/100= md/800---> md= 64g MS04
-LEGEA ELECTROLIZEI
m= AIt/ zF
19,2= Ax10x96,5x60/ 2x96,500 (am transformat minutele in secunde)
A= 64g/mol---> Cu----> CuSO4
- la Katod(-): Cu ²⁺ +2e----> Cu
-la Anod (+): 2OH⁻ -2e---> H2O+1/2O2
- md2=md1-19,2; md2= 64-19,2= >44,8g
ms2= ms1- m,M depus- m,apa consumata(pe care o neglijez)\
800-19,2=>780,8g
c2= 44,8x100/780,8=5,73%