8)
8^37=(2^3)^37=2^111
81^25=(3^4)^25=3^100
16^27=(2^4)^27=2^108
27^33=(3^3)^33=3^99
( 2^111 * 3^100 ) / ( 2^108 * 3^99 )= 2^3 * 3=8 * 3=24
Am scazut puterile intre numerele identice.
Adica:
2^n/2^(n-1) = 2^[n-(n+1)] = 2^(n-n+1) = 2^1. Sper ca ai inteles! ;)
