fie piramida VABC
- se traseaza VO _|_ (ABC), O se afla la intersectia medianelor bazei
- daca AM = mediana (si inaltime in ΔABC) AM = l√3 /2 AO = 2/3 ·l√3 /2
AO = l√3/3 = 8√3 /3 cm
a) - inΔVOA VO² = VA² - OA² = 256 - 64/3 = 704/3 = 8√11 cm
b) Al = P baza · apotema /2 = 3·24·√102 /2 = 36·√102 cm²
ap² = m² - l²/4 = 256 - 144 = 102
V = 1/3 ·l²√3 /4 ·h = 1/3 ·576√3 /4 ·8√11 = 384√33