ecuatia reactiei
1mol................................................0,5mol
CnH2n+2O +Na---> CnH2n+1ONa+1/2H2
14n+18 g alcool........... .0,5molH2.............0,2x22,4lH2
2,3g........................................................... .0,56 l
25,76=7,84n+10.08
n=2 verifica, te rog calculele !
este CH3-CH2OH alcoolul etilic