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Cite grame de brom pot aditiona: 3,5 grame de pentena; si 2 grame de butina

Răspuns :

CH2=CH-CH2-CH2-CH3+Br2---> CH2Br-CHBr-CH2-CH2-CH3
70g................................160g
3,5g.................................m= 8g brom

CH≡ C-CH2-CH3+2Br2---> CHBr2-CBr2-CH2-CH3
54g......................320g
2g.......................m= 11,85g brom