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Ajutor!!!
Aratati ca numarul de forma ab0 -ba/99 apartine multimii N


Răspuns :

   
[tex]\displaystyle \\ \frac{\overline{ab0} - \overline{ba}}{99}= \frac{100a + 10b +0 - (10b+a ) }{99}= \\ \\ = \frac{100a + 10b +0 - (10b+a ) }{99}= \\ \\ = \frac{100a + 10b +0 - 10b-a}{99}= \frac{100a -a}{99}= \frac{99a}{99}= \boxed{a} \in N ~~\text{(fiind cifra)}[/tex]