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Stiind ca 2a supra 9b = 1 supra 5 calculati valoarea raportului 2a-b supra 3a+b VA ROG URGENT!!

Răspuns :

[tex] \frac{2a}{9b} = \frac{1}{5} =\ \textgreater \ 10a=9b=\ \textgreater \ a= \frac{9b}{10} [/tex]

[tex]Fractia, \frac{2a-b}{3a+b} ,devine \frac{2( \frac{9b}{10} )-b}{3( \frac{9b}{10} )+b} [/tex]

[tex] \frac{ \frac{4b}{5} }{ \frac{37b}{10} } = \frac{4b}{5} * \frac{10}{37b} = \frac{8}{37} [/tex]
[tex]\frac{2a}{9b}= \frac{1}{5}=\ \textgreater \ 2a=9b* \frac{1}{5}=\ \textgreater \ a= \frac{9b* \frac{1}{5} }{2} \\ \frac{2a-b}{3a+b} \ \textless \ =\ \textgreater \ \frac{2( \frac{9b}{10})-b }{3( \frac{9b}{10})+b } = \frac{ \frac{9b}{5}-b }{ \frac{27b}{10} +b} = \frac{4*10b}{5*37b} = \frac{8}{37} [/tex]